What is the entire radial form of -3* cube root of 2?

I go cube root of 54 as my answer but it is wrong

-3* cube root of 2 is a negative number, so your result has to stay negative.

change it to

- cuberoot(54)

isn't negative not supposed to go inside the cube root

I have one more question

I tried this question but got the wrong answer...

3-x= √x^2-5

(The square root is over whole x^2-5)

My answer was x=2/3

squaring ... 9 - 6x + x² = x² - 5

x = 7/3

yes -∛54 = ∛-54

Did you try your answer for the other one??
(2/3)^2-5 is negative.
so its square root is not real

3-x = √(x^2-5)
9-6x+x^2 = x^2-5
6x = 14
x = 7/3

Let's try 7/3
3 - 7/3 = 2/3
√(49/9-5) = √4/9 = 2/3

Check the graphs at

http://www.wolframalpha.com/input/?i=plot+y%3D3-x,+y%3D%E2%88%9A(x%5E2-5)

To find the entire radical form of -3 times the cube root of 2, we can first simplify the cube root of 2 separately and then multiply it by -3.

The cube root (∛) of 2 is a value that, when raised to the power of 3, equals 2. To find the cube root of 2, we need to find a number that, when multiplied by itself three times, equals 2.

We can use approximation or a calculator to find that ∛2 is approximately equivalent to 1.26.

Now, we can multiply this value by -3:

-3 * (∛2) = -3 * 1.26 = -3.78

Therefore, the entire radical form of -3 times the cube root of 2 is approximately -3.78.