# Pre-Calculus 11

What is the entire radial form of -3* cube root of 2?

I go cube root of 54 as my answer but it is wrong

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1. -3* cube root of 2 is a negative number, so your result has to stay negative.

change it to

- cuberoot(54)

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2. isn't negative not supposed to go inside the cube root

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3. I have one more question

I tried this question but got the wrong answer...

3-x= √x^2-5

(The square root is over whole x^2-5)

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4. squaring ... 9 - 6x + x² = x² - 5

x = 7/3

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5. yes -∛54 = ∛-54

(2/3)^2-5 is negative.
so its square root is not real

3-x = √(x^2-5)
9-6x+x^2 = x^2-5
6x = 14
x = 7/3

Let's try 7/3
3 - 7/3 = 2/3
√(49/9-5) = √4/9 = 2/3

Check the graphs at

http://www.wolframalpha.com/input/?i=plot+y%3D3-x,+y%3D%E2%88%9A(x%5E2-5)

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