a bus weighing 50 tonnes moving with a velocity of 60km/hr.Calculate the force required to stop it in 10 seconds.

83500N

To calculate the force required to stop the bus, we need to use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the acceleration is the change in velocity over time.

First, we need to convert the mass and velocity to SI units:
- The mass of the bus is 50 tonnes, which is equivalent to 50,000 kg (1 tonne = 1000 kg).
- The velocity of the bus is 60 km/hr, which is equivalent to 16.67 m/s (1 km/hr = 0.2778 m/s).

Next, we need to calculate the acceleration. Since we know that the bus needs to stop in 10 seconds, the acceleration can be calculated using the formula a = Δv / t, where Δv is the change in velocity and t is the time taken.

Since the bus is moving with a velocity of 16.67 m/s and needs to come to a stop (v = 0 m/s), the change in velocity (Δv) is -16.67 m/s because the direction is opposite to the original velocity.

Now we can calculate the acceleration:
a = Δv / t = -16.67 m/s / 10 s = -1.67 m/s²

Finally, we can calculate the force required to stop the bus using Newton's second law:
F = m * a = 50,000 kg * -1.67 m/s²

Therefore, the force required to stop the bus in 10 seconds is -83,500 N (Newtons). The negative sign indicates that the force is opposite to the direction of motion, as it acts to decelerate the bus.

60 km/hr = 16.67 m/s

So, the acceleration is

-16.67m/s
-------------- = -1.67 m/s^2
10s

Since F = ma, now you can find F

Is the following statement true or false? Justify your answer using what you know about diameters and chords.

Every diameter of a circle is a chord.