Of the three angles of a triangle one is twice the smallest and another one is thrice the smallest. Find the angles
smallest --- x
middle one -- 2x
largest ------ 3x
x + 2x + 3x = 180
solve for x, sub back into my definitions
6X=180
X=180/6
X=30.
2x=2x30=60
3x=3x30=90.
The way of knowing the question is nice👌
To find the angles of a triangle, let's assume that the smallest angle is represented by 'x'.
According to the given information, one angle is twice the smallest, which means it can be represented as '2x'. Additionally, another angle is thrice the smallest, so we can represent it as '3x'.
The sum of the angles of a triangle is always 180 degrees. Therefore, we can write the equation:
x + 2x + 3x = 180
Simplifying the equation:
6x = 180
Dividing both sides of the equation by 6:
x = 30
Now that we know the value of 'x', we can find the angles:
The smallest angle = x = 30 degrees
The angle that is twice the smallest = 2x = 2 * 30 = 60 degrees
The angle that is thrice the smallest = 3x = 3 * 30 = 90 degrees
So, the three angles of the triangle are 30 degrees, 60 degrees, and 90 degrees.