1. Questions

CHEMISTRY

A 1.575 g sample of ethanedioic acid crystals, H2C2O4. xH20 was dissolved in water and made up to 250cm^3 . One mole of the acid reacts with two moles of NaOH. In a titration, 25.0 cm^3 of this solution of acid reacted with exactly 15.6 cm^3 of 0.160 mol/ dm^3 NaOH. Calculate the value of x

  1. 👍
  2. 👎
  3. 👁
Jack

  1. What exactly is x?

    1. 👍
    2. 👎
    👤
    bobpursley

  2. H2C2O4. x H20

    1. 👍
    2. 👎
    Clive

  4. H2C2O4 + 2NaOH ==> Na2CO2O4 + 2H2O
    1.575 g H2C2O4.xH2O in 250 mL and 25 cc of that makes the sample titrated 1.575 x (25/250) = 0.1575grams.

    mols NaOH = M x L = approx 0.0025 but you need to redo all of this with better numbers.
    Convert mols NaOH to mols H2C2O4.xH2O. 1/2 * 0.0025 = approx 0.0012
    mols H2C2O4.xH2O = grams/molar mass or
    molar mass = g/mol = approx 0.16/0.00125 = approx 128 for H2C2O4.xH2O. You know H2C2O4 is 90 so xH2O must be approx 128-90 = about 38.
    38/molar mass H2O = 38/18 = about 2 when rounded to a whole number so x must be 2.
    If you redo the problem without the estimates you will get x = 2.

    1. 👍
    2. 👎
    DrBob222

Respond to this Question

First Name

Your Response

Similar Questions

  1. Chemistry

    A sample of oxalic acid (H2C2O4, with two acidic protons), of volume 37.09 mL was titrated to the stoichiometric point with 22.41 mL of 0.163 M NaOH(aq). What is the molarity of the oxalic acid? Answer in units of M.

  2. Science

    Reggie has a sample of raw sugar made up of large particles and a sample of white sugar made up of much smaller particles. He dissolved 1 tsp. of each sample in 1 cup of water. Which dissolved fastest? a) Both dissolved at the

  3. Chem

    A 25.0 mL aliquot of a well-shaken and filtered sample of river is pipetted into an evaporating dish. The sample was heated to dryness. Assume the density of the river water was 1.01g/mL. The following data were collected for

  4. Chemistry

    If 1.50 g of H2C2O4 2H2O were heated to drive off the water of hydration, how much anhydrous H2C2O4 would remain? Thank you! Please explain clearly.

  1. Chemistry

    A sample of oxalic acid, H2C2O4, is titrated with standard sodium hydroxide, NaOH, solution. A total of 45.2 mL of 0.12 M NaOH is required to completely neutralize 20.0 mL of the acid. What is the concentration of the acid?

  2. Chemistry

    1.654 of a hydrated acid H2C2O4.xH2O was dissolved in water and the soultion was made up to 250cm3 . 23.80cm3 of this solution required 25.00cm3 of 0.100moldm-3 NaOH to reach the end point. Identify the value of x and the formula

  3. Chemistry

    Vinegar is a solution of acetic acid, CH3COOH, dissolved in water. A 4.69 g sample of vinegar was neutralized by 32.97 mL of 0.100 M NaOH. What is the percent by weight of acetic acid in the vinegar?

  4. Chemistry

    1.025g of an impure sample of a weak acid HX(mol mass = 82) is dissolved in 60ml of water and titrated with 0.25M NaOH. When half of the acid was neutralized the pH was found to be 5.0 and at the equivalence point the pH is 9.0.

  1. Analytical Chemistry

    Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibrium equation. CO2(g) CO2(aq) The acid dissociation constants listed in most standard reference texts

  2. physics

    If a bowl of salt water is left in the sun long enough for the water to evaporate a layer of salt crystals will be left in the bottom of the bowl. Salt crystals are more ordered than dissolved ions. How does the increase or

  3. Science

    A Sample of seaweed contains 1 Liter of water and has 50 grams of salt dissolved in its cells. The seaweed is placed in a solution made of 2 Liters of water and 150 grams of dissolved salt. What will occur when the system reaches

  4. Chemistry

    Pure water and Sodium chloride are both poor conductors of electricity by themselves. However, if sodium chloride crystals are dissolved into the water the solution becomes a good conductor of electricity. How does this phenomenon

You can view more similar questions or ask a new question.