Calculate the amount of heat in kilojoules released when 50 grams of steam at 125 C are convert to 50 grams of ice at 125 C please help

break the problem up and add the heats.

cool the steam to 100
condense the steam to water at 100
cool the water from 100 to O
freeze the water at 0C

I will be happy to critique your work.

thanks I think i got it now

and one more heat: the heat needed to be removed to cool the ice from 0 to -125C

To calculate the amount of heat released when steam at 125°C is converted to ice at the same temperature, you can use the following steps:

1. Determine the heat required to cool the steam from 125°C to its condensation point. This heat is given by the formula:

Q1 = m * c * (T2 - T1)

Where:
Q1 = heat required to cool the steam
m = mass of steam (in grams)
c = specific heat capacity of steam (2.03 J/g°C)
T1 = initial temperature (125°C)
T2 = condensation point of steam (100°C)

Plug in the values:
Q1 = 50 g * 2.03 J/g°C * (100°C - 125°C)

2. Determine the heat required for the phase change from steam at 100°C to water at 100°C (latent heat of vaporization). This heat is given by the formula:

Q2 = m * L

Where:
Q2 = heat required for phase change
m = mass of steam (in grams)
L = latent heat of vaporization of water (2260 J/g)

Plug in the values:
Q2 = 50 g * 2260 J/g

3. Determine the heat required to cool the water from 100°C to 0°C. This heat is given by the formula:

Q3 = m * c * (T4 - T3)

Where:
Q3 = heat required to cool the water
m = mass of water (in grams)
c = specific heat capacity of water (4.18 J/g°C)
T3 = initial temperature (100°C)
T4 = freezing point of water (0°C)

Since we have 50 grams of water, we can plug in the values:
Q3 = 50 g * 4.18 J/g°C * (0°C - 100°C)

4. Determine the heat required for the phase change from water at 0°C to ice at 0°C (latent heat of fusion). This heat is given by the formula:

Q4 = m * L

Where:
Q4 = heat required for phase change
m = mass of ice (in grams)
L = latent heat of fusion of water (334 J/g)

Since we have 50 grams of ice, we can plug in the values:
Q4 = 50 g * 334 J/g

5. Add up all the amounts of heat to get the total heat released:

Total heat released = Q1 + Q2 + Q3 + Q4

Calculate the total heat released using the values we obtained in the previous steps.

Note: The specific heat capacities and latent heat values provided are approximate average values. The actual values may vary slightly.