Calculate the amount of heat in kilojoules released when 50 grams of steam at 125 C are convert to 50 grams of ice at 125 C please help
break the problem up and add the heats.
cool the steam to 100
condense the steam to water at 100
cool the water from 100 to O
freeze the water at 0C
I will be happy to critique your work.
thanks I think i got it now
and one more heat: the heat needed to be removed to cool the ice from 0 to -125C
To calculate the amount of heat released when steam at 125°C is converted to ice at the same temperature, you can use the following steps:
1. Determine the heat required to cool the steam from 125°C to its condensation point. This heat is given by the formula:
Q1 = m * c * (T2 - T1)
Where:
Q1 = heat required to cool the steam
m = mass of steam (in grams)
c = specific heat capacity of steam (2.03 J/g°C)
T1 = initial temperature (125°C)
T2 = condensation point of steam (100°C)
Plug in the values:
Q1 = 50 g * 2.03 J/g°C * (100°C - 125°C)
2. Determine the heat required for the phase change from steam at 100°C to water at 100°C (latent heat of vaporization). This heat is given by the formula:
Q2 = m * L
Where:
Q2 = heat required for phase change
m = mass of steam (in grams)
L = latent heat of vaporization of water (2260 J/g)
Plug in the values:
Q2 = 50 g * 2260 J/g
3. Determine the heat required to cool the water from 100°C to 0°C. This heat is given by the formula:
Q3 = m * c * (T4 - T3)
Where:
Q3 = heat required to cool the water
m = mass of water (in grams)
c = specific heat capacity of water (4.18 J/g°C)
T3 = initial temperature (100°C)
T4 = freezing point of water (0°C)
Since we have 50 grams of water, we can plug in the values:
Q3 = 50 g * 4.18 J/g°C * (0°C - 100°C)
4. Determine the heat required for the phase change from water at 0°C to ice at 0°C (latent heat of fusion). This heat is given by the formula:
Q4 = m * L
Where:
Q4 = heat required for phase change
m = mass of ice (in grams)
L = latent heat of fusion of water (334 J/g)
Since we have 50 grams of ice, we can plug in the values:
Q4 = 50 g * 334 J/g
5. Add up all the amounts of heat to get the total heat released:
Total heat released = Q1 + Q2 + Q3 + Q4
Calculate the total heat released using the values we obtained in the previous steps.
Note: The specific heat capacities and latent heat values provided are approximate average values. The actual values may vary slightly.