Nadine dives with a senior swim club. In a dive off a 10m platform she reaches a maximum height of 10.5m after. 35s. How long does it take her to reach he water?
v(t) = v - 9.8t
v(0.35) = 0, so initial v = 3.43
Her height
y = 10 + 3.43t - 4.9t^2
So, solve for t when y=0
To determine how long it takes Nadine to reach the water, we need to consider the time it takes for her to reach the maximum height and then fall back down to the water.
Given that Nadine reaches a maximum height of 10.5m after 35s, we can assume that she spends half of the time going up and the other half coming down. Therefore, she spends 35s / 2 = 17.5s in each direction.
Since we are interested in the time it takes for her to reach the water, we can focus on the descending part. Nadine spends 17.5s coming down from the maximum height of 10.5m to reach the water. Therefore, it takes her 17.5 seconds to reach the water.
To find the time it takes for Nadine to reach the water, we first need to determine the time it takes her to reach the maximum height.
Given that Nadine reaches a maximum height of 10.5m after 35s, we can infer that Nadine's motion follows a parabolic path, which is symmetrical. Therefore, it takes Nadine half the time to reach the maximum height.
Hence, the time it takes for Nadine to reach the maximum height is 35s / 2 = 17.5s.
Since the total time of the dive includes both the ascent and descent, we can double the time it takes to reach the maximum height to find the total time of the dive.
Thus, it takes Nadine 17.5s * 2 = 35s to reach the water.