The problem is solve x= sqrt10x-4-2
So it would be x=sqrt10x-6 right
I have as x=4 is that right?
or is it 2,4
Read what I wrote about parentheses in one of your other posts. The answers are 2 and 4 IF the square root is taken of (10x-4).
correct the -2 is on the outside of the square root symbol.
<< the -2 is on the outside of the square root symbol>>
There is no way of knowing that, the way you originally wrote the problem. That is why parentheses are important when typing mathematical expressions
To solve the equation x = √(10x - 4) - 2, we can follow these steps:
1. Square both sides of the equation to eliminate the square root:
x^2 = (√(10x - 4) - 2)^2
2. Expand and simplify the right side of the equation:
x^2 = (10x - 4) - 4√(10x - 4) + 4
3. Rearrange the equation to isolate the square root term:
x^2 - 10x = -4 - 4√(10x - 4)
4. Move all terms to one side of the equation:
x^2 - 10x + 4 + 4√(10x - 4) = 0
Now, we can solve this quadratic equation by either factoring or using the quadratic formula.
Let's use the quadratic formula:
For a quadratic equation in the form ax^2 + bx + c = 0, the quadratic formula is:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our equation x^2 - 10x + 4 + 4√(10x - 4) = 0, we have:
a = 1, b = -10, c = 4 + 4√(10x - 4)
Substituting these values into the quadratic formula, we get:
x = [10 ± √((-10)^2 - 4 * 1 * (4 + 4√(10x - 4)))] / (2 * 1)
x = [10 ± √(100 - 16 - 16√(10x - 4))] / 2
x = [10 ± √(84 - 16√(10x - 4))] / 2
x = 5 ±√(84 - 16√(10x - 4))
So, we have two possible solutions for x, which are given by:
1. x = 5 + √(84 - 16√(10x - 4))
2. x = 5 - √(84 - 16√(10x - 4))
Unfortunately, it is not clear what values of x satisfy the equation without further calculations. Therefore, we cannot directly confirm if x = 4 or 2 are valid solutions to the equation x = √(10x - 4) - 2.