Polygon MNOPQ is dilated by a scale factor of 0.8 with the origin as the center of dilation, resulting in the image M′N′O′P′Q′. The coordinates of point M are (2, 4), and the coordinates of point N are (3, 5).The slope of MN is
steve if u did not know the answer there was no reason to say that, thats why u gotta dislike on ya shiii bc nobody fwu fr
whats the slope no one has answered als you have said so far where the coordinates of N
Slope is 1
To find the slope of line MN, we need to find the ratio of the change in y-coordinates to the change in x-coordinates between points M and N.
First, let's find the change in y-coordinates (Δy):
Δy = y2 - y1
= 5 - 4
= 1
Next, let's find the change in x-coordinates (Δx):
Δx = x2 - x1
= 3 - 2
= 1
The slope (m) of line MN can be calculated using the formula:
m = Δy / Δx
Substituting the values we found:
m = 1 / 1
m = 1
Therefore, the slope of line MN is 1.
Polygon MNOPQ is dilated by a scale factor of 0.8 with the origin as the center of dilation, resulting in the image M′N′O′P′Q′. The coordinates of point M are (2, 4), and the coordinates of point N are (3, 5).
The slope of is
.
not sure what the scaling has to do with anything, as the scaled polygon is never mentioned.
However, it should be easy to convince yourself that such a scaling does not change any of the slopes or angles involved.