The problem is solve x= sqrt10x-4-2
So it would be x=sqrt10x-6 right
then how would I solve for x
as drwls laid out, square both sides, then solve the quadratic.
I have the answer as x=4 is that right?
The -4 - 2 on the right looks suspicious. Did you really mean to write
x = sqrt(10x-4) -2 ?
The correct answer depends upon where the parentheses go.
4 is a correct answer,if the sqrt is taken of 10x -4. There is also another root.
To solve for x in the equation x = sqrt(10x - 4) - 2, it is not correct to simply write x = sqrt(10x - 6). Let's go through the steps to solve the equation correctly:
Step 1: Start by isolating the square root term on one side of the equation.
x + 2 = sqrt(10x - 4)
Step 2: To eliminate the square root, we need to square both sides of the equation.
(x + 2)^2 = (sqrt(10x - 4))^2
(x + 2)^2 = 10x - 4
Step 3: Expand the left side of the equation.
x^2 + 4x + 4 = 10x - 4
Step 4: Rearrange the equation by collecting like terms.
x^2 - 6x + 8 = 0
Step 5: Solve the quadratic equation. This equation can be factored as (x - 2)(x - 4) = 0, giving two potential solutions: x = 2 and x = 4.
Therefore, the solutions to the original equation x = sqrt(10x - 4) - 2 are x = 2 and x = 4.