Mr. Lakandula would like to increase his production of milkfish due to its high demand in the market. He is thinking of making a larger fishpond in his 8000 sq. m lot near a river. Help Mr. Lakandulaby making a sketch plan of the fishpond to be made. Out of the given sutuation and the sketch plan made, formulate as many quadratic equations then solve by factoring.
Cannot sketch here.
Sir ramos ito pala yung pinaactivity mo sa amin
I DOT'N NO MA'
AM
I don't know the answer, please help me
Project for math
To help Mr. Lakandula make a sketch plan of his fishpond, we need to consider a few factors such as the shape and dimensions of the fishpond. The given information states that Mr. Lakandula has an 8000 sq. m lot near a river. However, we need more details to create an accurate sketch plan.
1. Shape of the Fishpond:
There are various shapes to consider for the fishpond, such as rectangular, square, circular, or irregular. Let's assume Mr. Lakandula wants to create a rectangular fishpond.
2. Dimensions of the Fishpond:
To determine the dimensions, we need more information. Let's assume Mr. Lakandula wants a rectangular fishpond with a length of 2x meters and a width of x meters.
Now, let's create a sketch plan of the fishpond based on the assumptions:
L = 2x meters
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With this sketch plan, we can formulate quadratic equations based on the area and solve them by factoring.
Area of a Rectangle:
The area of a rectangle is given by the formula A = length * width.
1. Equation for the Area of the Fishpond:
Area = Length * Width
8000 = (2x) * x
8000 = 2x^2
This is the quadratic equation representing the area of the fishpond. To solve it by factoring, we need to rewrite it in standard quadratic form:
2x^2 - 8000 = 0
Now, to solve the equation by factoring, we can factor out the common factor of 2:
2(x^2 - 4000) = 0
Now, set each factor equal to zero:
x^2 - 4000 = 0
(x - 200)(x + 200) = 0
x - 200 = 0 or x + 200 = 0
x = 200 or x = -200
Since the width cannot be negative, the appropriate solution is x = 200.
Therefore, Mr. Lakandula should create a rectangular fishpond with a length of 2x = 2(200) = 400 meters and a width of x = 200 meters to utilize his 8000 sq. m lot effectively.