Calculate the pH of a solution containing 10 g / L of NH4Cl (Kb NH3 = 1.8x10-5
This is a hydrolysis equation.
M NH4Cl = mols/L = grams/molar mass/L = approx 0.2 but you need to redo all of these calculations.
......NH4^+ + H2O ==> H3O^+ + NH32
I....0.2...............0.......0
C.....-x...............x.......x
E.....0.2-x............x.......x
Ka for NH4^+ = (Kw/Kb for NH3) = (x)(x)/(0.2-x) and solve for x = (H3O^+). Convert to pH.