Calculate the pH of a solution containing 10 g / L of NH4Cl (Kb NH3 = 1.8x10-5

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  1. This is a hydrolysis equation.
    M NH4Cl = mols/L = grams/molar mass/L = approx 0.2 but you need to redo all of these calculations.
    ......NH4^+ + H2O ==> H3O^+ + NH32

    Ka for NH4^+ = (Kw/Kb for NH3) = (x)(x)/(0.2-x) and solve for x = (H3O^+). Convert to pH.

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