# Physics

A 6.0 V battery is being used to charge a 5.0x10^-6 F capacitor through a resistor R. The capacitor attains a potential difference of 3.6 V in 1 second after the charging begins. The value of the resistance R is?

Been stuck on this for a while and if anyone can point me into the right direction that will be great.

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1. V=6(1-e^t/rc)

3.6/6=1-e^1/rc
take ln of both sides
ln(.6)=0+-1/rc

r=-ln(.6)/5E-6

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bobpursley
2. Oh ok, thank you.

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