the perimeter of a rectangle is 270 meters. find its dimension if the width is 3/4 of its length. <- our teacher gave us that question and whoever gets the correct answer gets extra credit AND I DON'T KNOW HOW TO DO IT HELP
2 (L+w) = 270
L + .75 L = 135
1.75 L = 135
L = 135/1.75 etc
To solve this problem, you can begin by setting up algebraic equations based on the given information. Let's assume the length of the rectangle is "L" meters and the width is "W" meters.
According to the problem, the width (W) is 3/4 of the length (L). This can be expressed as:
W = (3/4)L
The perimeter of the rectangle is given as 270 meters. Perimeter is the sum of all sides of a shape. For a rectangle, the perimeter can be calculated as:
Perimeter = 2L + 2W
Substituting the value of W from the first equation into the second equation, we get:
270 = 2L + 2(3/4)L
Now, we can solve this equation to find the value of L.
270 = 2L + (3/2)L
270 = (4/2)L + (3/2)L
270 = (7/2)L
To isolate L, we can multiply both sides of the equation by (2/7):
L = (270 * 2/7)
L = 540/7
L ≈ 77.14 meters
Now, we can substitute this value back into the equation W = (3/4)L to find the width:
W = (3/4)(77.14)
W = 57.86 meters
Therefore, the dimensions of the rectangle are approximately 77.14 meters in length and 57.86 meters in width.