Physics

What % increase in momentum if increase of k.e is 23%
A. 46%
B. 33%
C. 50%
D. 11%
E. 46%

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  1. (1/2) m v2^2 = 1.23 (1/2) m v1^2

    so
    v2 = sqrt(1.23) v1

    v2 = 1.11 v1

    well, that is an 11% increase

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  2. Thx sir

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  3. Answer is correct but I cannot understand formula which you have written.

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  4. ke=1/2 m v^2
    for ke increase of 23 precent, new KE is 1.23 of original
    1.23*1/2 mvi^2=1/2 m v'^2

    v'=vi*sqrt 1.23

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    bobpursley

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