# Physics

What % increase in momentum if increase of k.e is 23%
A. 46%
B. 33%
C. 50%
D. 11%
E. 46%

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1. (1/2) m v2^2 = 1.23 (1/2) m v1^2

so
v2 = sqrt(1.23) v1

v2 = 1.11 v1

well, that is an 11% increase

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2. Thx sir

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3. Answer is correct but I cannot understand formula which you have written.

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4. ke=1/2 m v^2
for ke increase of 23 precent, new KE is 1.23 of original
1.23*1/2 mvi^2=1/2 m v'^2

v'=vi*sqrt 1.23

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bobpursley

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