the difference of two positive number is 69 the quotient obtained on dividing one by the the other is 4 find the numbers

x-y = 69

x/y = 4 ---> x = 4y

sub into the first:
4y - y = 69
3y = 69
y = 23 , then x = 4(23) = 92

Let two numbers be x and y

ATQ
X - Y=69
X/Y=4
X=4Y
X-Y=69
4y-y=69
3y=69
Y=69/3
Y=23
X=4×23
X=92

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The difference between the ages of two sisters is 10years if 15years ago the elder one was twice as old as the younger one find their present ages.

To find the two numbers, let's assign variables and set up equations based on the given information.

Let's assume the two positive numbers are x and y, where x is greater than y.

We are given two conditions:

1. The difference of two positive numbers is 69:
x - y = 69

2. The quotient obtained on dividing one number by the other is 4:
x / y = 4

Now, we have a system of equations that can be solved simultaneously.

To solve these equations, we can use either substitution or elimination method.

Let's solve them using the substitution method:

From equation 2, we have:
x = 4y

Substitute the value of x from equation 2 into equation 1:
4y - y = 69
3y = 69
Divide both sides by 3:
y = 23

Now, substitute the value of y into equation 2 to find x:
x = 4 * 23
x = 92

Therefore, the two numbers are 23 and 92.

The difference of two positive numbers is 69. The quotient obtained on dividing one by the other is 4. Find the number.

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