A gun fires 300 bullets per minute horizontally with a velocity of 500ms-1 . Each bullets mass us 3*10^-3 kg. what is the force needed to hold the gun in position????

To determine the force needed to hold the gun in position, we need to consider the concept of Newton's second law of motion. Newton's second law states that the force acting on an object is equal to its mass multiplied by its acceleration.

In this example, the gun is firing bullets horizontally, which means it is experiencing a recoil force in the opposite direction. The force required to hold the gun in position is equal to the force exerted by the bullets.

To calculate the force exerted by the bullets, we need to find the change in momentum of the bullets. The change in momentum is given by the equation:

Δp = m * Δv

Where
Δp = change in momentum
m = mass of the bullets
Δv = change in velocity

Since the bullets are fired horizontally and have a velocity of 500 m/s, the change in velocity is 500 m/s. The mass of each bullet is given as 3 * 10^-3 kg.

Δp = (3 * 10^-3 kg) * (500 m/s) = 1.5 kg·m/s

However, the gun fires 300 bullets per minute, which means there are 300 bullets fired in 60 seconds. To find the force exerted by the bullets in one minute, we need to divide the change in momentum by the time:

Force = Δp / t

Where
Force = force exerted by the bullets
Δp = change in momentum
t = time

Converting one minute to seconds:

60 seconds

Plugging in the values:

Force = (1.5 kg·m/s) / (60 s) = 0.025 kg·m/s²

Therefore, the force needed to hold the gun in position is approximately 0.025 Newtons.