100g of water is added into 10.6m NaOH solution.What is the mol fraction of NaOH in the diluted NaOH solution. Density of NaOH is 1.08g/ml
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To find the mole fraction of NaOH in the diluted solution, we first need to calculate the amount of NaOH in grams and moles after the dilution.
Step 1: Calculate the amount of NaOH in grams:
Volume of NaOH solution = 10.6 mL
Density of NaOH = 1.08 g/mL
Using the density formula: Mass = Volume × Density
Mass of NaOH in the 10.6 mL solution = 10.6 mL × 1.08 g/mL
Step 2: Calculate the amount of NaOH in moles:
Molar mass of NaOH = 22.99 + 16.00 + 1.01 = 40.00 g/mol (23.0 g/mol + 16.0 g/mol + 1.0 g/mol)
Amount of NaOH in moles = Mass of NaOH / Molar mass of NaOH
Step 3: Calculate the total amount of solution in grams after dilution:
100 g (mass of water) + 10.6 g (mass of NaOH)
Step 4: Calculate the mole fraction of NaOH:
Mole fraction of NaOH = Amount of NaOH in moles / Total amount of solution in moles
Now, let's calculate the values:
Step 1: Mass of NaOH in the 10.6 mL solution = 10.6 mL × 1.08 g/mL = 11.448 g
Step 2: Amount of NaOH in moles = 11.448 g / 40.00 g/mol = 0.2862 mol
Step 3: Total amount of solution in grams after dilution = 100 g + 10.6 g = 110.6 g
Step 4: Mole fraction of NaOH = 0.2862 mol / (0.2862 mol + 1.0 mol) ≈ 0.221
Therefore, the mole fraction of NaOH in the diluted NaOH solution is approximately 0.221.