The shadow of pole at a particular time of day is 1√3 times the height of pole. What is the elevation of the source of light?
height ---- h
shadow length ----- √3
tanØ = h/√3h = 1/√3
Ø = ??
you should be familiar with the angle whose tangent is 1/√3
btw, I suspect a typo in 1√3, since we normally would not put that 1 in front of a radical.
was it 1/√3 ?
If so, make the necessary changes