A three-digit code is made up of three different digits from the set (2,4,6,8). How many three-digit codes can be formed if no digit is repeated?
Since in a code, the order matters, it would be
4x3x2 or 24
To find the number of three-digit codes that can be formed with three different digits from the set (2, 4, 6, 8) without repetition, we can use the concept of combinations.
There are four possible choices for the first digit, four for the second digit, and three for the third digit (since repetition is not allowed). Therefore, the total number of three-digit codes that can be formed is:
4 choices for the first digit * 4 choices for the second digit * 3 choices for the third digit = 4 * 4 * 3 = 48.
Hence, there are 48 different three-digit codes that can be formed without repeating any of the digits from the set (2, 4, 6, 8).