number of grams of MgCl2 needed to prepare a 250ml of a 12% aqueous solution with 1.1g/ml density
To determine the number of grams of MgCl2 needed to prepare a 250 mL of a 12% aqueous solution with a density of 1.1 g/mL, we need to follow the following steps:
Step 1: Calculate the volume of MgCl2 needed.
Since we want to prepare a 250 mL solution, we need to know the volume percentage of the final solution. The 12% concentration means that we will have 12 mL of MgCl2 in a total volume of 100 mL. Thus, the volume of MgCl2 needed can be calculated as:
Volume of MgCl2 = (12 / 100) x 250 mL
Volume of MgCl2 = 30 mL
Step 2: Calculate the mass of MgCl2.
To find the mass of MgCl2, we can use the density of the solution. We know that the density is 1.1 g/mL. Therefore:
Mass of MgCl2 = Volume x Density
Mass of MgCl2 = 30 mL x 1.1 g/mL
Mass of MgCl2 = 33 grams
So, to prepare a 250 mL of a 12% aqueous solution with a density of 1.1 g/mL, you will need 33 grams of MgCl2.