If 5.00g of glucose were to react completely with an excess of oxygen, how many grams of carbon dioxide would be produced?
5/180 = 1/36
1/36 * 6 ( 6 moles of CO2 for everyone one of Glucose) = 1/6
1/6 * 44 = 7.3333333 grams of CO2 produced
C6H12O6 + 6O2 => 6CO2 + 6HOH
5g C6H12O6 = (5/180)mole C6H12O6 = 0.028mole C6H12O6
Fm equation ... if ...
1 mole C6H12O6 => 6 moles CO2
then 0.028 mole C6H12O6 => 6(0.028) mole CO2 = 0.468mole CO2 => grams CO2 = (0.468mole CO2)(44g/mol) 20.6g CO2(g)
To determine the grams of carbon dioxide (CO2) produced when 5.00g of glucose (C6H12O6) reacts completely with oxygen (O2), we need to use the balanced chemical equation for the combustion of glucose.
The balanced equation for the combustion of glucose is as follows:
C6H12O6 + 6O2 → 6CO2 + 6H2O
This equation indicates that for every 1 mole of glucose, 6 moles of carbon dioxide are produced.
To calculate the grams of carbon dioxide produced, we need to follow these steps:
Step 1: Convert grams of glucose to moles of glucose.
First, we need to determine the molar mass of glucose (C6H12O6). By adding the atomic masses of carbon, hydrogen, and oxygen, we find that the molar mass of glucose is approximately 180.156 g/mol.
To convert grams of glucose to moles, divide the given mass (5.00g) by the molar mass of glucose:
5.00g / 180.156 g/mol = 0.02777 mol (rounded to five decimal places)
Step 2: Use the mole ratio to find moles of carbon dioxide.
According to the balanced equation, for every 1 mole of glucose, 6 moles of carbon dioxide are produced. So, we can multiply the moles of glucose by the mole ratio to find the moles of carbon dioxide:
0.02777 mol glucose × 6 mol CO2 / 1 mol glucose = 0.1666 mol CO2 (rounded to four decimal places)
Step 3: Convert moles of carbon dioxide to grams.
Finally, we can calculate the grams of carbon dioxide by multiplying the moles of carbon dioxide by the molar mass of carbon dioxide. The molar mass of CO2 is approximately 44.01 g/mol.
0.1666 mol CO2 × 44.01 g/mol = 7.33 g CO2 (rounded to two decimal places)
Therefore, if 5.00g of glucose reacts completely with an excess of oxygen, approximately 7.33 grams of carbon dioxide would be produced.