Calculus

Two sides of a triangle have constant lengths a and b, and the angle between them is theta. What value of theta will maximize the area of the triangle?

so far i have the formula and the derivative.
A=.5absin(theta)
A'=.5abcos(theta)

then i set the derivative to zero in order to get the critical point, but i don't know how to solve it because if I divide zero by .5, it will just be 0.

0=.5abcos(theta)

can anyone help me get past this step? thanks.

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asked by Nathaniel
  1. you almost in there already, think about the cos(theta) = 0, it means the theta=90 degree, so, you got it

    posted by charles

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