Math HELPPPPP

a) Find the gradient of the line x/7+y/11=1.
b) the straight line Y=mx+c is parallel to the line y+ 5/3x=7/3 and passes through the point (2,3). Find the values of m and c

The answer for a is -11/7x
And b us 6 1/3

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  1. x/7+y/11=1
    multiply each term by 77, the LCD
    11x + 7y = 77
    7y = -11x + 77
    y = (-11/7)x + 11

    the gradient or slope is -11/7
    (in your answer you included the variable)

    b)
    y+ 5/3x=7/3 , or
    y = (-5/3)x + 7/3

    the slope is -5/3 , so
    Y=mx+c ----> Y = (-5/3)x + c
    if (2,3) lies on it,
    3 = (-5/3)(2) + c
    c = 3 + 10/3
    c = 19/3
    so you are correct with 6 1/3

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