# Math HELPPPPP

a) Find the gradient of the line x/7+y/11=1.
b) the straight line Y=mx+c is parallel to the line y+ 5/3x=7/3 and passes through the point (2,3). Find the values of m and c

The answer for a is -11/7x
And b us 6 1/3

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1. x/7+y/11=1
multiply each term by 77, the LCD
11x + 7y = 77
7y = -11x + 77
y = (-11/7)x + 11

the gradient or slope is -11/7

b)
y+ 5/3x=7/3 , or
y = (-5/3)x + 7/3

the slope is -5/3 , so
Y=mx+c ----> Y = (-5/3)x + c
if (2,3) lies on it,
3 = (-5/3)(2) + c
c = 3 + 10/3
c = 19/3
so you are correct with 6 1/3

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