Write formulas for the compounds that form from Sr and each of the following polyatomic ion: NO−3, SO2−4, PO3−4.
APPARENTLY SrNO6, SrSO4 , Sr3PO8 is wrong
You must keep the ions in their proper proportions.
NO3 is the ion, so changing it to NO6 is bogus. Maybe you should try (NO3)2
Or, if NO is the ion, then (NO)3 would give you three of them.
the 3 is the charge
yeah - sorry. I read some of your other posts and saw what was going on.
To determine the correct formulas for compounds formed from Sr (strontium) and each polyatomic ion, it's important to know the charges of the ions involved. Let's break down each polyatomic ion and its charge:
1. Nitrate ion (NO−3): The NO−3 ion has a charge of -1. Since Strontium (Sr) is a Group 2 element, it has a charge of +2. To form a neutral compound, the charges must balance. Therefore, we need two nitrate ions for every strontium ion. The formula for the compound is Sr(NO3)2.
2. Sulfate ion (SO2−4): The SO2−4 ion has a charge of -2. Following a similar approach as before, two strontium ions are needed to balance the charges. The formula for the compound is Sr2(SO4).
3. Phosphate ion (PO3−4): The PO3−4 ion has a charge of -3. To balance the charges, three strontium ions are needed. The formula for the compound is Sr3(PO4)2.
Therefore, the correct formulas for the compounds formed from Sr and each polyatomic ion are Sr(NO3)2, Sr2(SO4), and Sr3(PO4)2.