Write formulas for the compounds that form from Sr and each of the following polyatomic ion: NO3 −1, SO4 −2, PO4 −3.
SR (+3 CHARGE)
NO3(-1 CHARGE)
SO4(-2 CHARGE)
PO4(-3 CHARGE)
Re posting this question. hopefully someone can help me answer this now. Please answer to this question.
i posted my work in the original posting
But you know those answers are wrong. You should follow my rules above to get the correct answers.
To determine the formulas for the compounds formed between Sr and each of the given polyatomic ions, we need to consider the charges on each ion and balance them to obtain a neutral compound.
1. Nitrate ion (NO3^-1):
Since the nitrate ion has a charge of -1, and strontium (Sr) has a charge of +3, we need 3 nitrate ions to balance the charge. Therefore, the formula for the compound formed is Sr(NO3)3.
2. Sulfate ion (SO4^-2):
The sulfate ion has a charge of -2, and strontium has a charge of +3. To balance the charges, we need two sulfate ions. Thus, the formula for the compound is SrSO4.
3. Phosphate ion (PO4^-3):
The phosphate ion has a charge of -3, and strontium has a charge of +3. Using the charges, we can write the formula by swapping the absolute values of the charges. Thus, the formula for the compound is Sr3(PO4)2.
Remember to always balance the charges to obtain an electrically neutral compound.
Here is how you do a couple of them. Then you try the others.
Sr and NO3^-1
Sr is a +2 charge. There is no Sr with a +3 charge.
Sr(NO3)2. You can see Sr is +2 and 2 NO3^- is -2 so the +2 neutralizes the -2. All compounds will be zero charge and that's how you know what numbers to use for each ion. For the sulfate (SO4^2- it is SrSO4. The easy way to do this is to write the ions down like this
SrNO3. Place the +2 charge over the Sr and the -1 charge over the NO3. Now DRAW and X (mentally) with the left diagonal over the Sr at the top and the bottom of the left diagonal under the NO3^-. The right diagonal is done the same way with the top over the NO3^- and the bottom under the Sr. Move the numbers down the diagonal at the top to the bottom of THAT diagonal; i.e., the 2 moves the the bottom right (which means 2 NO3^-) and the 1 moves to the bottom left (which means 1 for Sr). Ignore the signs. You need not write the 1 (that's understood) and if the numbers you get (like SrSO4 would be Sr2(SO4)2, reduce those to the smallest numbers; i.e., 1 so SrSO4 is what you end up with. Hope this helps. I shall be happy to check your answers or answer any questions.