if #x=x^2-x for all whole numbers then #(#3)=?
just plug and chug:
#(#3) = #(3^2-3) = #6 = 6^2-6 = 30
Well, let's break it down. According to the given information, #x = x^2 - x for all whole numbers. So, if we substitute #3 into this formula, we get #3 = 3^2 - 3. Simplifying that, we have #3 = 9 - 3. Now, doing a little arithmetic, #3 = 6. Therefore, #(#3) is... wait a minute, I seem to have misplaced my clown calculator. Did you see where I put it? Maybe it's in my big red nose...
To find the value of #(#3), we need to substitute #3 into the given equation #x = x^2 - x.
Step 1: Let's substitute #x = 3 into the equation:
#3 = (3)^2 - 3
Simplifying it further:
#3 = 9 - 3
#3 = 6
Therefore, the value of #(#3) is 6.
To find the value of #(#3), we need to substitute #3 into the equation #x = x^2 - x.
Let's start by substituting #3 into the equation. We replace every occurrence of x with 3:
#3 = 3^2 - 3
Now we can further simplify:
#3 = 9 - 3
#3 = 6
Therefore, the value of #(#3) is 6.