can someone correct this for me or help me. 6x^2y^3+ 9x^2y^3 divided by 3x^2y^2 my solving and answer is: 15 x x y y y ---------- = 5y 3 x x y y Looks good to me. I've never thought of showing x^2y^3 as xxyyy. That a neat wrinkle.
I need to find the value of x. 9x^3 + 9x = 30x^2 It's confusing because apparently I have to do 9x^3 + 9x and then add the + 30x^2 to it, and then make it equal 0, so it ends up like this: 9x^3 + 9x + 30x^2 = 0 And afterward, I
the Q is : Given that (1+ax)^n = 1 + 30x +375x^2+.... find the values of the constants a and n . I know that : (i am writing (n 1) as the coefficient of n) (n 1) *ax = 30x (n 2) *(ax)^2 = 375x^2 which can be written as (n 1)* a =
9x^2+16y^2-18x+64y-71=0 find the coordinates of the center, the foci, and the vertices of this ellipse. 9x^2+16y^2-18x+64y-71=0 9x^2-18x+16y^2+64y=71 9(x^2-2x)+16(y^2+4y)=71 9(x^2-2x+1)+16(y^2+4y+4)=71