What volume of 6M NaOH needed to prepare 250ml 0.1M NaOH?
How many mols do you need? That's M x L = ? mols NaOH.
Then grams = mols NaOH x molar mass NaOH
5 mL
To find the volume of 6M NaOH needed to prepare 250ml of 0.1M NaOH, we can use the formula:
M1 x V1 = M2 x V2,
where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.
In this case, M1 (initial molarity) is 6M, V1 (initial volume) is what we want to find, M2 (final molarity) is 0.1M, and V2 (final volume) is 250ml.
Rearranging the formula, we can solve for V1:
V1 = (M2 x V2) / M1.
Substituting the given values:
V1 = (0.1M x 250ml) / 6M.
V1 = 4.17 ml (rounded to two decimal places).
So, you would need approximately 4.17 ml of 6M NaOH to prepare 250ml of 0.1M NaOH.