On a day that is 30°c, you drop a rock from the top of a well. You hear the sound of the rock hitting the bottom 0.6s after you drop it. How deep is the well?

find v, the speed of sound. If the depth of the well is y, then the time taken for the sound to come back is y/v

Using the equation of motion, we have
4.9t^2 = y
Thus, the time it takes to hit the water is √(y/4.9)

Adding up the times, we have

√(y/4.9) + y/v = 0.6

Plugging in your value for v, you just need to solve that for y.

To determine the depth of the well, we can use the principles of motion and the concept of free fall.

The equation to calculate the distance an object falls, ignoring air resistance, is given by the formula:

d = (1/2) * g * t^2

Where:
d = distance (depth of the well)
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time it takes for the rock to hit the bottom of the well (0.6s in this case)

Plugging in the given values, we have:

d = (1/2) * 9.8 * 0.6^2
d = (1/2) * 9.8 * 0.36
d = 1.764 meters (rounded to three decimal places)

Therefore, the depth of the well is approximately 1.764 meters.