A cash register contains $5 bills and $10 bills with a total value of $350. If there are 46 bills total, then how many of each does the register contain?
answer is 22
No.
5x + 10y = 350
x + y = 46
I have the same equation you have figure out.
i figure out the problem i receive this answer 22
x = 5 dollar bills
y = 10 dollar bills
5x + 10y = 350
x + y = 46
x = 46 - y
5(46-y) + 10y = 350
230 - 5y + 10y = 350
5y = 120
y = 24
There are 24 ten-dollar bills and 22 five-dollar bills.
24 tens and 22 five
Timothy has $350 in $10 and $20 bills in his cash drawer. If the number of $10 bills is three times the number of $20 bills, how many of each are in the drawer?
To solve this problem, we can set up a system of equations based on the given information.
Let's assume "x" represents the number of $5 bills and "y" represents the number of $10 bills in the cash register.
We can then create the following equations:
1) The total number of bills: x + y = 46
2) The total value of all the bills: 5x + 10y = 350
To solve this system of equations, we can use the method of substitution or elimination.
Let's use the substitution method to solve this system:
From equation 1), we can express x in terms of y:
x = 46 - y
Now, substitute this expression for x in equation 2):
5(46 - y) + 10y = 350
Simplifying the equation:
230 - 5y + 10y = 350
5y = 350 - 230
5y = 120
y = 120 / 5
y = 24
Now, substitute the value of y back into equation 1) to find x:
x + 24 = 46
x = 46 - 24
x = 22
Hence, there are 22 $5 bills and 24 $10 bills in the cash register.