A square 1 m on its side has charges on every corner. Calculate the electric field on the upper right corner of the square. Let the charge on each corner be 40 x10-9C.
Do I use K(Q*4)/r^2=F
Then F/(Q*4)=E
K=8.99*10^9 Nm^2/C^2
Yes, you are correct in using the formula for electric field (E) which is E = K(Q/r^2), where K is the electrostatic constant (8.99 x 10^9 Nm^2/C^2), Q is the charge, and r is the distance from the charge.
In this case, each corner of the square has a charge of 40 x 10^(-9) C. The electric field is to be calculated at the upper right corner.
To calculate the electric field at the upper right corner, you need to determine the distance (r) from the charge on the upper right corner to the point where you want to calculate the electric field.
Since it's a square with sides of 1m, the distance from any corner to the opposite corner (diagonal) will be sqrt(2) times the side length. In this case, it will be sqrt(2) x 1m = sqrt(2) m.
Now, substitute the known values into the formula:
E = (8.99 x 10^9 Nm^2/C^2) * (40 x 10^(-9) C) / (sqrt(2) m)^2
Simplifying further:
E = (8.99 x 40 / 2) N/C
E = 359.6 N/C
Therefore, the electric field at the upper right corner of the square is 359.6 N/C.