The A note has a frequency of 880 Hz. What is the wavelength if the speed of sound is 343 m/s?


0.39 m

2.57 m

537 m

301,000 m

Which speed(s) is/are below the sound barrier in air?
A. 257 m/s

B. 1,030 m/s

C. 10 m/s

frequency*wavelength=speed

wavelength=speed/frequency.

1030 is above the speed of sound in air.

To find the wavelength, we can use the formula:

wavelength = speed / frequency

Given that the frequency is 880 Hz and the speed of sound is 343 m/s, we can substitute these values into the formula:

wavelength = 343 m/s / 880 Hz

Calculating this, we find that the wavelength is approximately 0.39 m.

So, the correct answer is:

0.39 m

Next, let's determine which speed(s) is/are below the sound barrier in air.

The sound barrier is the speed at which an object moves at or above the speed of sound. The speed of sound in air is approximately 343 m/s.

Comparing the given speeds:

A. 257 m/s: This speed is below the sound barrier in air.

B. 1,030 m/s: This speed is above the sound barrier in air.

C. 10 m/s: This speed is below the sound barrier in air.

So, the correct answer is:

A. 257 m/s
C. 10 m/s

To find the wavelength, we can use the formula:

Wavelength = Speed / Frequency

Given that the frequency is 880 Hz and the speed of sound is 343 m/s, we can substitute the values into the formula:

Wavelength = 343 m/s / 880 Hz

Calculating this, we get:

Wavelength = 0.39 m

So, the wavelength for the A note with a frequency of 880 Hz and a speed of sound of 343 m/s is 0.39 m.

Now, let's determine which speeds are below the sound barrier in air. The sound barrier is the speed at which an object is traveling at or above the speed of sound. In air, the speed of sound is approximately 343 m/s.

Comparing the given speeds:

A. 257 m/s - This speed is below the sound barrier, as it is lower than 343 m/s.

B. 1,030 m/s - This speed is above the sound barrier, as it is higher than 343 m/s.

C. 10 m/s - This speed is below the sound barrier, as it is lower than 343 m/s.

Therefore, speeds A and C are below the sound barrier in air.