How many terms of arithmethic sequence with the common difference of 4. And the first is equal to 3 and the last term 59??
(59 - 3) / 4 = 14
14 + 1 = 15 terms
To find the number of terms in an arithmetic sequence, given the common difference, first term, and last term, you can use the following formula:
number of terms = (last term - first term) / common difference + 1
Let's apply this formula to your question:
common difference = 4
first term = 3
last term = 59
number of terms = (59 - 3) / 4 + 1
number of terms = 56 / 4 + 1
number of terms = 14 + 1
number of terms = 15
Therefore, there are 15 terms in the arithmetic sequence.