Two ships leave a lighthouse from opposite directions.The speed of ship A is 8 Km/h faster than ship B. at the end of 60 hours the two ships are 4320 km apart. Find the speed of two ships
The speeds are x and x+8
since distance = speed * time
60(x + x+8) = 4320
60(x+x+8)=4320 60x+60x+480=4320 120x=4320-480 x= 3840/120 x=32
To find the speeds of the two ships, we can set up a system of equations using the given information.
Let's assume the speed of ship B is x km/h. The speed of ship A is then (x + 8) km/h, since it is 8 km/h faster than ship B.
Now, let's consider the distance traveled by each ship in 60 hours. Ship A travels at a speed of (x + 8) km/h for 60 hours, covering a distance of (x + 8) * 60 km. Ship B travels at a speed of x km/h for 60 hours, covering a distance of x * 60 km.
Given that the two ships are 4320 km apart at the end of 60 hours, we can set up the following equation:
(x + 8) * 60 + x * 60 = 4320
Let's solve this equation to find the value of x, which represents the speed of ship B:
60x + 480 + 60x = 4320
120x + 480 = 4320
120x = 4320 - 480
120x = 3840
x = 3840 / 120
x = 32
So, the speed of ship B is 32 km/h.
To find the speed of ship A, we can use the equation (x + 8):
Speed of ship A = 32 + 8 = 40 km/h.
Therefore, the speed of ship A is 40 km/h and the speed of ship B is 32 km/h.