math

If the zeroes of the quadratic polynomial x^2+(a+1)x+bare 1& -3 find a&b

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  1. well, geez, just plug in the values. You have

    (x-1)(x+3)
    = x^2 + 2x - 3 = x^2 + (a+1)x + b

    Now it should be clear what a and b are if the two polynomials are identical.

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  2. Most likely the topic is the Sum and Product of roots of a quadratic
    for ax^2 + bx + c = 0
    sum of roots = -b/a
    product of roots = c/a

    given:
    sum of roots = -3+1 = -2
    product of roots = -3

    then -(a+1) = -2
    a = 1

    b/1 = -3
    b = -3

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  3. oh, yeah. Good call.

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