A bullet leaves a rifle with a muzzle velocity of 521 m/s .while accelerating through the barrel of the rifle , the bullet moves a distance of 0.840m.determine the acceleration if the bullet. (Assume a uniform acceletlration).
this is not correct answer
To determine the acceleration of the bullet, we can use the equation for uniformly accelerated motion:
v^2 = u^2 + 2as
Where:
v = final velocity of the bullet (muzzle velocity)
u = initial velocity of the bullet (0 m/s, since it starts from rest)
a = acceleration of the bullet
s = distance covered by the bullet in the barrel
Rearranging the equation to solve for acceleration:
a = (v^2 - u^2) / (2s)
Substituting the given values into the equation:
a = (521^2 - 0^2) / (2 * 0.840)
Simplifying the equation:
a = (271441 - 0) / 1.68
a = 271441 / 1.68
a ≈ 161521.43 m/s^2
Therefore, the acceleration of the bullet is approximately 161521.43 m/s^2.
Vf^2=vi^2+2*acceleration*distance
solve for acceleration
I have 2 answers
1. u=521m/s
v=0
s= 0.840
now we use v^2=u^2+2as
0^2=521^2+2xax0.840
0=2771441+1.68a
1.68a=2771441
a= 2771441 by 1.68
a=161572.02
that's the first answer
2.velocity= distance by time
velocity = 521ms
distance = 0.840m
therefore time =0.840 by 521
=0.0016s
a=velocity by time
=521 by 0.0016 = 325625ms^2
that's my second answer
please help