two forces are in the ratio 1:2 named p and q.if their resultant is at an angle tan inverse root 3 /2 to vector p then the angle between p and q is ?

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  1. first find the angle:
    tan^-1 Theta=3/2 draw a right triangle, opposite side 3, adjacent 2, then hypotenuse is sqrt5
    Sin Theta=3/sqrt5 from the drawing.

    Law of sines:
    where last angle is between resultant and side 2
    sinlast angle=1.5 /sqrt5
    put this into your google search engine:
    inverse sine(1.5 /sqrt 5) in degrees=

    Now, determine the last angle:
    angle between p and q is 180-lastangle-givenagnle

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