two bus start from the same bus stand at 8a.m. one travels at 40km/h and other at 50km/h. the second bus reaches the next stop at 10a.m.How much later will the first bus arrive?
distance covered=50km/hr*2hrs=100km
time for slow bus:
time=100km/40km/hr=2.5hr
so it will arrive 30 min later
2 hrs at 50km/hr = 100 km
So, how long does it take to go that far at 40 km/hr?
How 2.5 hr becomes 30 min? Can anyone explain it?
To find out how much later the first bus will arrive, we need to calculate the time taken by the first bus to reach the next stop after 10 a.m., since the second bus arrives at 10 a.m.
We know that the second bus travels at a speed of 50 km/h, and it reaches the next stop at 10 a.m. This means it took 2 hours for the second bus to cover the distance between the bus stand and the next stop.
Now, let's determine the distance between the bus stand and the next stop. The time taken by both buses to reach the next stop is the same i.e., 2 hours. We can apply the distance formula to find the distance:
Distance = Speed × Time
For the second bus:
Distance = 50 km/h × 2 hours
Distance = 100 km
Therefore, the distance between the bus stand and the next stop is 100 km.
Now, let's calculate the time taken by the first bus to cover the same distance. We have the speed of the first bus, which is 40 km/h, and the distance, which is 100 km.
Time taken by the first bus = Distance / Speed
Time taken by the first bus = 100 km / 40 km/h
Time taken by the first bus = 2.5 hours
Since the second bus arrived at the next stop at 10 a.m., and the first bus takes an additional 2.5 hours, the first bus will arrive:
10 a.m. + 2.5 hours = 12:30 p.m.
Therefore, the first bus will arrive 2 hours and 30 minutes (or 2.5 hours) later than the second bus.