A 5.0 m portion of wire carries a current of 8.0 A from east to west. It experiences a magnetic field of 6.0 × 10^–4 T running from north to south. What is the magnitude and direction of the magnetic force on the wire?
2.4 × 10^–2 N upward
2.4 × 10^–2 N downward
1.2 × 10^–2 N downward
1.2 × 10^–2 N upward
Upward? Downward? What directions are those?
It force will be out of the plane, toward the observer. Is that Upward?
To determine the magnitude and direction of the magnetic force on the wire, you can use the formula for the magnetic force on a current-carrying wire:
F = BIL sin(θ)
Where:
F is the magnetic force
B is the magnetic field strength
I is the current
L is the length of the wire
θ is the angle between the direction of the current and the magnetic field
In this case, the wire is carrying a current of 8.0 A from east to west, and it experiences a magnetic field of 6.0 × 10^–4 T running from north to south.
First, let's consider the direction of the magnetic force. The right-hand rule tells us that if the current is flowing from east to west and the magnetic field is running from north to south, the force will be directed upward.
Next, we can calculate the magnitude of the magnetic force using the given values:
F = (6.0 × 10^-4 T) * (8.0 A) * (5.0 m) * sin(90°)
Since sin(90°) is equal to 1, the formula simplifies to:
F = (6.0 × 10^-4 T) * (8.0 A) * (5.0 m)
F = 2.4 × 10^-2 N
So, the magnitude of the magnetic force on the wire is 2.4 × 10^-2 N, directed upward.
Therefore, the correct answer is: 2.4 × 10^-2 N upward.