4NH3 + 5O2 --> 4NO + 6H2O

170g of ammonia (NH3) are allowed to react with 384g of O2.

how many moles of NO is produced? and also how many grams of NO will be produced?

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  1. figure the moles of NH3 in 170g.
    now figure the moles of O2 in 384g

    if you have 5/4 more moles of O2 than NH3, then NH3 is the limiting reageant. Moles NO=molesNH3*
    if you have less than 5/4 moles of O2, then O2 is limiting. Moles NO = 4/5 moles of O2 reacted.

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