if a water tank is 3feet*3feet*3feet how much water it will contain and if it is circular case and diameter is of 5feet n height 5feet
This just does not make sense.
a 3x3x3 ft^3=27ft^3
it cannot be circular case if it is a cube
maybe they're separate problems. In that case, just use the normal formula
v = π/4 d^2 h
and use your numbers
To calculate the volume of a rectangular water tank, you need to multiply its length, width, and height. The given dimensions of the rectangular water tank are 3 feet by 3 feet by 3 feet. So, the volume of the rectangular water tank can be calculated as follows:
Volume = Length * Width * Height
Volume = 3 feet * 3 feet * 3 feet
Volume = 27 cubic feet
Therefore, the rectangular water tank will contain 27 cubic feet of water.
To calculate the volume of a cylindrical water tank, you need to use the formula for the volume of a cylinder, which is π * r^2 * h, where π is a mathematical constant (approximately 3.14159), r is the radius of the circular base, and h is the height of the cylinder.
The given dimensions of the cylindrical water tank are a diameter of 5 feet and a height of 5 feet. The radius of the circular base can be calculated by dividing the diameter by 2.
Radius = Diameter / 2
Radius = 5 feet / 2
Radius = 2.5 feet
Using the given values, we can calculate the volume of the cylindrical water tank as follows:
Volume = π * r^2 * h
Volume = 3.14159 * (2.5 feet)^2 * 5 feet
Volume ≈ 98.17468 cubic feet
Therefore, the cylindrical water tank will contain approximately 98.17468 cubic feet of water.