A tortoise and a hare race against each other. A hare runs at a constant speed of 36 km per hour for exactly ten seconds and waits for the tortoise to catch up. If the tortoise takes two hours to move 1 km, how long will it take to catch up?
36 km/hr times 1 hr/3600 sec
I used 3600 because there are 60 min in 1 hour and 60 sec in 1 min.
36 km/3600 sec times 10 sec
360/3600 = he would be 1/10 or .1 km
The tortoise takes 2 hours to go 1 km
rate is .5 km/ hour
chance to kim/sec .5/3600 tortoise'rate
He has to catchup so he has to go .1 km
d = rt
.1 =.5/3600 t
.1 times 3600/.5 = time in seconds.
To find out how long it will take for the hare to catch up to the tortoise, we need to determine how far the tortoise will have moved during the 10 seconds that the hare runs.
We know that the hare runs at a constant speed of 36 km/h for 10 seconds. So, the distance covered by the hare during this time is:
Distance = Speed × Time
Distance = 36 km/h × (10 seconds / 3600 seconds/hour) [converting seconds to hours]
Distance = 36 km/h × 10/3600 hour
Distance ≈ 0.1 km
Therefore, the tortoise needs to cover a distance of approximately 0.1 km to catch up to the hare.
Given that the tortoise moves at a speed of 1 km per 2 hours, we can calculate the time it takes for the tortoise to cover the required distance.
Time = Distance / Speed
Time ≈ 0.1 km / (1 km/2 hours)
Time = 0.1 km × (2 hours / 1 km)
Time ≈ 0.2 hours
Converting 0.2 hours to minutes:
0.2 hours × 60 minutes/hour ≈ 12 minutes
Therefore, it will take the tortoise approximately 12 minutes to catch up to the hare.