The number of boys is 3 more than double the girls. Together, there are 54 students in total. How many boys and girls are there?

g + 2g + 3 = 54

3g = 51

g = 17

Let's use algebra to solve this problem step by step.

Step 1: Assign variables to the unknowns.
Let's use 'b' to represent the number of boys and 'g' to represent the number of girls.

Step 2: Translate the given information into equations.
The number of boys is 3 more than double the number of girls can be written as:
b = 2g + 3

The total number of students is 54, which can be written as:
b + g = 54

Step 3: Solve the system of equations.
Substitute the value of b from the first equation into the second equation:
(2g + 3) + g = 54

Combine like terms:
3g + 3 = 54

Subtract 3 from both sides:
3g = 51

Divide both sides by 3:
g = 17

Now substitute the value of g back into the first equation to find the value of b:
b = 2(17) + 3
b = 34 + 3
b = 37

Therefore, there are 37 boys and 17 girls.

To find the number of boys and girls, we can set up a system of equations based on the given information.

Let's assume the number of girls is x.
According to the given information, the number of boys is 3 more than double the girls, which can be expressed as: 2x + 3.

The total number of students is 54, so the equation can be written as:

x + (2x + 3) = 54

Simplifying the equation, we have:

3x + 3 = 54

Subtracting 3 from both sides, we get:

3x = 51

Dividing both sides by 3, we get:

x = 17

Therefore, there are 17 girls (x) and the number of boys is:

2x + 3 = 2(17) + 3 = 34 + 3 = 37

So, there are 17 girls and 37 boys in total.

Girls=x boys=2x+3 Total students = 54 =2x+3+x=54 =5+2x=54 =7x=54 =x=54/7 =x=7.72