solve the equation:3(x-2)^2-12=0
3 ( x - 2 ) ^ 2 - 12 = 0 Divide both sides by 3
3 ( x - 2 ) ^ 2 / 3 - 12 / 3 = 0 / 3
( x - 2 ) ^ 2 - 4 = 0 Add 4 to both sides
( x - 2 ) ^ 2 - 4 + 4 = 0 + 4
( x - 2 ) ^ 2 = 4 Take square root of both sides
x - 2 = + OR - sqroot ( 4 )
x - 2 = + OR - 2
1 solution :
x - 2 = - 2 Add 2 to both sides
x - 2 + 2 = - 2 + 2
x = 0
2 solution :
x - 2 = 2 Add 2 to both sides
x - 2 + 2 = 2 + 2
x = 4
The solutions are :
x = 0 and x = 4