Well someone please help me with this problem!!!!!!!!!!!!
From a base elevation of 8200ft. a mountain peak in colorado rises to a summit elevation of 14701ft.over a horizontal distance of 15838 ft. Find the grade of the peak.
The grade of the peak is what percent?
(Round to the nearest tenth as needed)
The summit rise is 14701-8200 = 6501 feet. The "grade" is that rise divided by the horizontal distance, expressed as a percent.
Just to quibble a bit, there are no mountains in Colorado that are that high. Grade numbers are usually applied to roads and areas of constant slope, NOT to entire mountains.
Whoever dreamed up this question needs a refresher course in math and geography
Thank you so much drwl.
To find the grade of the peak, we can use the formula:
Grade = (Change in elevation / Horizontal distance) * 100
In this case, the change in elevation is the difference between the summit elevation (14701 ft) and the base elevation (8200 ft), which is:
Change in elevation = 14701 ft - 8200 ft = 6501 ft
The horizontal distance is given as 15838 ft.
Using the formula, we can now calculate the grade of the peak:
Grade = (6501 ft / 15838 ft) * 100
To calculate this, we divide the change in elevation by the horizontal distance, and then multiply by 100 to convert it to a percentage.
Simplifying the calculation:
Grade = (0.4107) * 100
Grade ≈ 41.1
Therefore, the grade of the peak is approximately 41.1 percent when rounded to the nearest tenth.