Writing the net ionic equation for sodium fluoride+hydrochloride,
magnesium iodide + lead (II) acetate
sliver (I) acetate + potassium iodide
nickel (II) sulfate + barium chloride
barium acetate + ammonium sulfate
barium hydroxide +aluminum bromide
zinc iodide + potassium hydroxide
ammonium carbonate + silver (I) acetate
cobalt (II) iodide + potassium phosphate
potassium sulfide + aluminum bromide
zinc iodide +sulfide
Review Metathesis (Double Replacement Rxns)
=> AX + BY => AY + BX
One of the compounds on the product side will be a insoluble precipitate, weak acid or base or a gas decomposition product. The 'Driving Force' compound prevents the reaction from reversing.
1. NaF + HCl => NaCl + HF
'HF' is a weak acid. The weak acid if formed because 'H' forms a relatively strong bond with 'F' and has a much lower tendency to remain ionized as is the other compound (NaCl) on the product side. When writing the ionic equation, All compounds that have high ionization potential are written as ions in aqueous solution. The 'Driving Force' compound is written in molecular form.
Ionic Equation:
(Na^+) + (F^-) + (H^+) (Cl^+) => (Na^+) + (Cl^-) + (HF)
Net Ionic Equation shows only the ions reacting to form the 'Driving Force' compound. The other ions (Na^+) & (Cl^-) are spectator ions and are not included in the 'Net' Ionic Equation.
(H^+) + (F^-) => (HF)
The 'Driving Force' compound in second reaction above is Lead(II) Iodide. It has a very low ionization potential compared to the other ionic compounds that are part of the reaction.
MgI2 + Pb(OAc)2 => Mg(OAc)2 + PbI2(s)
(Mg^+2) + 2(I^-) + (Pb^+2) + 2(OAc^-) => (Mg^+2) + 2(OAc^-) + PbI2(s)
(Pb^+2) + 2(I^-)=> PbI2(s) [net ionic equation]
To ID the driving force of a Metathesis Rxn, you must learn the solubility rules. The salt compounds that have low solubility are typically the Driving Force compound in Salt + Salt => Salt + Ppt(s)
To ID the driving force of a reaction producing a weak acid, you need to learn the '6' strong acids. HCl, HBr, HI, HClO4, HNO3, and H2SO4(1st ionization step). If the acid is not a member of the 'Strong 6' then it will be a weak acid driving force compound. In the 1st problem, HF is the driving force b/c it is a weak acid and not a member of the 6 Strong Acid set.
The Driving force in problem ...
3. => Silver Iodide
4. => Barium Sulfate
5. => Barium Sulfate
6. => Aluminum Hydroxide
7. => Zinc Hydroxide
8. => Silver(I) Carbonate
9. => Cobalt(II)Phosphate
10.=> Aluminum Sulfide
11.=> Zinc Sulfide
To write the ionic equations, list all reactants in ionic form unless there is a weak acid or weak base => Molecular Formula of Driving Force Cpd + Ionic Form of the remaining ionic compound (salt). Cancel out the 'Spectator Ions' => Net Ionic Equation.