CU+H2SO4>CUSO4+H2O+SO2
I am wondering what the question is.
The chemical equation presented is a balanced equation for the reaction between copper (Cu) and sulfuric acid (H2SO4) to form copper sulfate (CuSO4), water (H2O), and sulfur dioxide (SO2).
To understand how to balance this equation and determine the products, we need to follow a few steps:
Step 1: Write down the chemical formula for each reactant and product:
Cu + H2SO4 → CuSO4 + H2O + SO2
Step 2: Balance the equation by making sure there is an equal number of atoms on both sides of the equation. Start with the elements that are present in the least number of compounds. In this case, we start with Cu and balance it on both sides:
Cu + H2SO4 → CuSO4 + H2O + SO2
Step 3: Balance the hydrogen (H) atoms by adjusting the coefficient in front of H2O:
Cu + H2SO4 → CuSO4 + 2H2O + SO2
Step 4: Balance the sulfur (S) atoms. In this case, since there is only one sulfur atom in both reactants and products, it is already balanced.
Cu + H2SO4 → CuSO4 + 2H2O + SO2
Step 5: Finally, balance the oxygen (O) atoms. On the left side, we have 4 oxygen atoms in sulfuric acid (H2SO4), and on the right side, there are 6 oxygen atoms in copper sulfate (CuSO4) and water (H2O). To balance them, we add a coefficient of 3 in front of H2SO4:
Cu + 3H2SO4 → CuSO4 + 2H2O + SO2
Now the equation is balanced, and it shows that one copper atom reacts with three sulfuric acid molecules to form one copper sulfate molecule, two water molecules, and one sulfur dioxide molecule.