solve for X and Y.
125x + 5y = 21
1.5x + 1/2y = 3
clearing fractions and decimals, we have
125x + 5y = 21
3x + y = 3
now you can substitute y = 3-3x to get
125x + 5(3-3x) = 21
Now it's easy to solve for x, and then you can get y.
To solve this system of equations, we can use the method of substitution or elimination. Let's use the method of substitution.
Step 1: Choose one equation and solve for one variable in terms of the other variable. Let's solve the second equation for x.
1.5x + (1/2)y = 3
Multiply both sides of the equation by 2 to get rid of the fraction:
3x + y = 6
Rearrange the equation to solve for y:
y = 6 - 3x
Step 2: Substitute the expression for y into the other equation. Let's substitute y in the first equation:
125x + 5(6 - 3x) = 21
Step 3: Simplify and solve for x.
125x + 30 - 15x = 21
Combine like terms:
110x + 30 = 21
Subtract 30 from both sides:
110x = 21 - 30
110x = -9
Divide both sides by 110:
x = -9/110
Step 4: Substitute the value of x back into one of the original equations to solve for y. Let's substitute x in the second equation:
1.5(-9/110) + (1/2)y = 3
Simplify:
(-13/220) + (1/2)y = 3
Multiply both sides of the equation by 220 to get rid of the fraction:
-13 + 110y = 660
Combine like terms:
110y = 660 + 13
110y = 673
Divide both sides by 110:
y = 673/110
So the solution to the system of equations is x = -9/110 and y = 673/110.