24. A radio signal travels at 3.00 x 10^8 meters per second. How many seconds will it take for a radio signal to travel from a satellite to the surface of Earth if the satellite is orbiting at a height of 3.54 x 10^7 meters?
im guessing its 118 seconds but im not sure..
Bro I need the answer, not a pity party
(3.54 x 10^7) divided by (3.00 x 10^8)
divide 3.54 by 3.00 = 1.18
10^7-8 = 10^-1
1.18 x 10^-1
Bro calm down. Don't say that about yourself. Whatever other people say or do never ever say that about yourself.
I'm also wondering about this question any help?
Sooo do we devide the 3.54 and 3 or subtract them?
wait, so, how did you get 3.54 when it's 3.00???
To calculate the time it takes for a radio signal to travel from a satellite to the surface of the Earth, you can use the formula:
Time = Distance / Speed
In this case, the distance between the satellite and the Earth's surface is given as 3.54 x 10^7 meters, and the speed of the radio signal is 3.00 x 10^8 meters per second.
Plugging these values into the formula:
Time = (3.54 x 10^7 meters) / (3.00 x 10^8 meters per second)
Now, let's simplify the equation:
Time = (3.54 / 3.00) x 10^7 / 10^8
To divide powers of 10, subtract the exponents:
Time = 1.18 x 10^(-1) seconds
Finally, we convert the decimal exponent to seconds:
Time = 1.18 x 0.1 seconds
Calculating the multiplication:
Time = 0.118 seconds
Therefore, it would take approximately 0.118 seconds for the radio signal to travel from the satellite to the surface of the Earth, not 118 seconds as you initially guessed.